synchcola | Mar. 13th, 2007

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Mar. 13th, 2007

happy pi day!

$\pi$ ²ⁿ = 2^2n-1/2n! [(-1)^n-1 B_2n] (1 + 1/4ⁿ + 1/9ⁿ + ...)

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synchcola

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