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Dec. 9th, 2006 04:52 pmAha, so someone (Chris Ware?) has already come up with the idea of head tracking for correct perspective on a monitor rather than an immersive environment. Also, there is a head tracker available cheap. (the "trackir 4") So what I want to think about now is: what has to be done for it to become popular? It would totally catch on if only there were a nice application! But for the most part the head tracker is being used as a convenient control device for the view. So I think this is wrong. I am pretty sure that there is a really awesome way to use this technique.
Head tracking in, like, a first-person game? It's useless since everything is so far away. The ideal application for head tracking takes place in a square box the size of the monitor. Like Yellow Pages Except With A Model Of The City, Google Earth, Second Life, or what.
I am never sure if algebraic topology is idiotically simple and I'm even stupider, or very complicated so that I'm having a typical time.
Also, pf that fc: Z → YX is continuous iff f: X x Z → Y is. The space YX has the compact-open topology. The space X is locally compact (?) Let (x, z) ∈ X x Z, and f(x, z) is in a neighbourhood U. Let A be a rel compact neighbourhood of x. If fc is continuous, then fc(Z)(A) ⊂ U for some neighbourhood Z so f is all continuousy. If f is continuous, then let fc(z)(A) ⊂ U. Sets f(Z,A') ⊂ U cover the set (z,A).Look at ∪ Z. Edit. I suck: f(∩ Z, ∪ A) ⊂ U.
Head tracking in, like, a first-person game? It's useless since everything is so far away. The ideal application for head tracking takes place in a square box the size of the monitor. Like Yellow Pages Except With A Model Of The City, Google Earth, Second Life, or what.
I am never sure if algebraic topology is idiotically simple and I'm even stupider, or very complicated so that I'm having a typical time.
Also, pf that fc: Z → YX is continuous iff f: X x Z → Y is. The space YX has the compact-open topology. The space X is locally compact (?) Let (x, z) ∈ X x Z, and f(x, z) is in a neighbourhood U. Let A be a rel compact neighbourhood of x. If fc is continuous, then fc(Z)(A) ⊂ U for some neighbourhood Z so f is all continuousy. If f is continuous, then let fc(z)(A) ⊂ U. Sets f(Z,A') ⊂ U cover the set (z,A).
